Focal chord of y 2 16x is a tangent

WebDec 1, 2024 · Focal chord of the parabola is tangent to the circle (x−6)^2+y^2=2. 2and (6,0) are radius and centre of the circle . As radius is perpendicular to the tangent, we have length of tangent from (4,0) to … WebThe focal chord to y2 =64x is tangent to (x−4)2+(y−2)2 =4 then the possible values of the slope of this chord is Q. The focal chord to y2 =16x is tangent to (x−6)2+y2 =2, then the possible value of the slope of this chord are Q. The focal chord to y2 =16x is tangent to (x−6)2+y2 =2, then slope of focal chord is Q.

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WebApr 10, 2024 · Even by your method where it seems you are first finding equation of tangent to the circle and equating it to the focal chord, Given the equation of the circle, taking … WebSOLUTION. Here, the focal chord of y2 =16x is tangent to circle (x−6)2+y2 = 2. ⇒ Focus of parabola as (a,0) i.e. (4,0) Now, tangents are drawn from (4,0) to (x−6)2+y2 = 2. Since, P … easiest medical schools to get accepted https://paulwhyle.com

Answered: 5. K 53% 65° L N M m/JKL= bartleby

WebMar 14, 2024 · It is given that the focal chord is tangent to the circle which means that the distance of the focal chord from the center of the circle is equal to the radius of the circle. Therefore, we get m x − y − 4 m 1 + m 2 = 2 Now we will put the value of x = 6 and y = 0 in the above equation, we get ⇒ 6 m − 0 − 4 m 1 + m 2 = 2 WebQ.3 Find the equations of the tangents to the parabola y2 = 16x, which are parallel ... y = 2x + 1 (C) 2y = x + 8 (D) y = x + 2 Q.10(a) The slope of the focal chords of the parabola y2 = 16x which are tangents to the circle (x ... [ JEE 2003 (Scr.)] Q.6 The line 2x + 6 y = 2 is a tangent to the curve x2 – 2y2 = 4. The point ... WebDec 1, 2024 · Focal chord of the parabola is tangent to the circle (x−6)^2+y^2=2. 2and (6,0) are radius and centre of the circle As radius is perpendicular to the tangent, we have length of tangent from (4,0) to the circle is = 2 . From the diagram, we have tan teta= 2/ 2=1⇒θ=45 Therefore, slope of the chord is ±1= (−1,1). Advertisement Answer ctv seth

The locus of centroid of triangle formed by a tangent to the parabola y ...

Category:The focal chord to y^2 = 16 x is tangent to (x - 6)^2

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Focal chord of y 2 16x is a tangent

geometry - Prove that the directrix is tangent to the circles that …

WebA: Here, Circle with center O is having tangents JK, KL and JL. so JA¯≅JB¯ ⇒JA=JB (tangent to circle… question_answer Q: Find the surface area of the cone in terms of it. WebFocal chord to y 2 = 16 x i s t a n g e n t t o (x − 6) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are Q. The focal chord to y 2 = 16 x is tangent to ( x − 6 ) 2 …

Focal chord of y 2 16x is a tangent

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WebA chord which passes through the focus of a parabola is called a focal chord. A given chord will be a focal chord if the point \((0,a)\) lies on it. Substituting these coordinates into the equation of the chord above we have ... and substituting \(x=2ap\). In either case, the gradient of the tangent to \(x^2=4ay\) at the point \(P(2ap,ap^2 ... WebThe focal chord to \( y^{2}=16 x \) is tangent to \( (x-6)^{2}+y^{2}=2 \), then the possible values of theslope of this chord are\( P \)(a) \( \{-1,1\} \)\( ...

WebA: y=-2sin3x+90∘y=-2cos3x ∵sin90+θ=cosθ Sketch two cycle of the given trigonometric… question_answer Q: Find the value of each variable using the given chord and secant lengths. WebMay 6, 2016 · Question: Prove that the directrix is tangent to the circles that are drawn on a focal chord of a parabola as diameter. ... Prove that in a parabola the tangent at one end of a focal chord is parallel to the normal at the other end. 0.

WebJan 23, 2024 · Solution For The focal chord to y2=16x is tangent to (x−6)2+y2=2, then the possible values of the slope of this chord, are The world’s only live instant tutoring platform. About Us Become a Tutor. Filo instant Ask button for chrome browser. Now connect to a tutor anywhere from the web ... WebFocal chord to y2=16x is tangent to x−62+y2=2 then the. Focal chord to y2 =16x is tangent to (x−6)2+y2 =2 then the possible values of the slopes of this chord (s),are. …

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WebIf the fotal chord y = mx + c of parabola y^2=-64x is also the tangent to the circle 〖(x+10)〗^2+y^2=4 then absolute value of 4√2(m+c) is (a) 31(b) 32(c... easiest mediterranean diet to followWebStep-1 Length of tangent : Given: The focal chord to y 2 = 16 x is tangent to (x – 6) 2 + y 2 = 2. The standard equation of the parabola is: y 2 = 4 a x. Comparing the given … ctv set up accountWebThe focal chord of the parabola (y−2) 2=16(x−1) is a tangent to the circle x 2+y 2−14x−4y+51=0, then the focal chord can be A 0 B 1 C 2 D 3 Medium Solution Verified by Toppr Correct option is B) Was this answer helpful? 0 0 Similar questions If points (au 2,2au) and (av 2,2av) are extremities of the focal chord of a parabola y 2=4ax, then Hard ctv shades of irelandWebJun 27, 2016 · Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site easiest med school to get intoWeb2) are the endpoints of a focal chord then t 1 t 2 = −1. (2) Tangents at endpoints of a focal chord are perpendicular and hence intersect on directrix. (3) Length of a focal chord of y2 = 4ax, making an angle αwith the X-axis, is 4acosec2α. (4) If AB is a focal chord of y2 = 4ax, then , where S is the focus. Recall ctv shannon bradburyWebHere, the focal chord of y 2 = 16 x is tangent to circle (x − 6) 2 + y 2 = 2 ⇒ Focus of parabola as (a, 0) i.e. (4, 0) Now, tangents are drawn from (4, 0) to (x − 6) 2 + y 2 = 2. Since, P A is tangent to circle. ∴ t a n θ = slope of tangent = A C A P = √ 2 √ 2 = 1, or B C B P = − 1. ∴ Slope of focal chord as tangent to circle ... easiest medical university to get into ukWebClick here👆to get an answer to your question ️ The focal chord to y ^ 2 = 16 x is tangent to ( x - 6 ) ^ 2 + y ^ 2 = 2 then the possible values of the slope of this chord are Solve Study Textbooks Guides easiest medical coding jobs