WebDec 12, 2013 · The problem with using typeid(*this).name() is that there is no this pointer in a static method call. The macro __PRETTY_FUNCTION__ reports a class name in static … WebJul 28, 2024 · RTTI is run-time type information, which should not be needed in the case of non-polymorphic typeid ... But this is a compiler switch, not a language feature, so you …
c++ - unordered_map error in GCC - Stack Overflow
Web#include #include #include struct empty { }; template struct bar { }; int main() { int status; char *realname; // typeid … WebDec 20, 2010 · To create the application executable that uses the library: g++ -s -fno-rtti -o app code.cpp -DAPP -L. -lmodule -Wl,-rpath,. This application, compiled with the -fno-rtti will crash since the application does not include RTTI information and even though it does not itself use it, the library does. the puritans by jack cavanaugh
activate RTTI in c++ - Stack Overflow
WebMay 6, 2013 · Strange output of std::typeid::name () I used typeid to get the type names of the std::vector::size_type and a zero sized class A with the following code ( cppreference … WebC++ lambda函数的类型,c++,c++11,lambda,typeid,C++,C++11,Lambda,Typeid,有以下代码: auto fun = [](int x)->int {return x + 1; }; std::cout << typeid(fun).name() << std::endl; auto-fun=[](intx)->int{return x+1;}; 标准(§5.1.2)未规定lambda函数的类型: lambda表达式的类型(也是闭包对象的类型)是唯一的、未命名的非联合类类型,称为闭 ... WebJan 24, 2012 · 5. First, as mkaes points out, you cannot put assignments outside functions, so you have to put it in any, for example main. As for unordered_map, for recent versions of gcc, if you don't want to go into C++11, you can use the TR1 version of unordered_map: #include . and the type std::tr1::unordered_map. the puritans believed